This page says the following:

When Bash is interactive, in the absence of any traps, it ignores SIGTERM (so that `kill 0' does not kill an interactive shell), and SIGINT is caught and handled (so that the wait builtin is interruptible). When Bash receives a SIGINT, it breaks out of any executing loops.

Usually when a program receives the SIGINT signal, the program will exit. But bash does not exit when it receives the SIGINT signal, instead "it breaks out of any executing loops". What does that mean?