Usually the date +%d gives the output 08 for current date, 08/10/2017. But when I do the ls -lrt on a path, the date format is like Oct 8 15:03, so, how to get the files of the current date?

I'm using a command

ls -lrt XYZ.LOG* |grep "$(date +'%b %d')" |awk '{print $9}'

but it's not giving me the file of today's date (08/10/2017) although it gives me correct output for the dates 10 - 31st of any month.

Usually the date +%d gives the output 08 for the current date, 08/10/2017. But when I do the ls -lrt on a path, the date format is like Oct 8 15:03, so, how do I get the files of the current date?

I'm using the command

ls -lrt XYZ.LOG* |grep "$(date +'%b %d')" |awk '{print $9}'

but it's not giving me the file of today's date (08/10/2017) although it gives me correct output for the dates 10 - 31st of any month.

Usually the date +%d gives the output : 08 for current date : 08/10/2017. But when i do the ls -lrt on a path,the date format is like Oct 8 15:03, so, how to get the files of the current date. I'm using a command : ls -lrt XYZ.LOG* |grep "$(date +'%b %d')" |awk '{print $9}' but it's not giving me the file of today's date(08/10/2017) although it gives me correct output for the dates 10 - 31st of any month.

Usually the date +%d gives the output 08 for current date, 08/10/2017. But when I do the ls -lrt on a path, the date format is like Oct 8 15:03, so, how to get the files of the current date?

I'm using a command

ls -lrt XYZ.LOG* |grep "$(date +'%b %d')" |awk '{print $9}'

but it's not giving me the file of today's date  (08/10/2017) although it gives me correct output for the dates 10 - 31st of any month.