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lang-c
b = gensub(/(.+) (.+)/, "\\2 \\1", "g", a), are\1and\2evaluated by the function or before calling the function? Why does it work? (2) Doessubstr(s[1],2)return the suffice of strings[1]starting from the second character ofs[1]? Will its output include the last character,?\1and\2in the string passed to gensub will get replaced by gensub for every match. But the string passed to gensub stays otherwise fixed. In your post you try to provide an expression, but that must be converted into a string (which can contain\1) before it gets passed to gensub. Thesubstrcall is as you described, it starts from character position 2 until the end.gensub(/\/([0-9]+),/, "/" (\\1+3) ","), what will\\1+3in the second argument become after evaluating and then what will it become after converting to string?