Timeline for unix: get characters 10 to 80 in a file
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Apr 7, 2017 at 8:47 | history | edited | Stéphane Chazelas | CC BY-SA 3.0 |
added 165 characters in body
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| Apr 7, 2017 at 8:43 | vote | accept | gugy | ||
| Apr 7, 2017 at 8:25 | vote | accept | gugy | ||
| Apr 7, 2017 at 8:25 | |||||
| Apr 6, 2017 at 19:17 | comment | added | hschou |
It is best if you change the original question. Show exactly what the input and the output is and then someone would come with a solution. I'm not a sed expert but this one should do it: cat file | sed -n -e '/>scaffold_2/,$p' | grep -v '^>' | cut -zc 10-80 but I think grep could be avoided with the right sed option. (this cut-thing is good).
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| Apr 6, 2017 at 13:19 | comment | added | gugy | I like this solution! can it be modified to only start counting after the occurence of >scaffold_2 ? the current answer ignores the lines starting with >, but counts from the beginning of the file, if I understand correctly? | |
| Apr 6, 2017 at 12:43 | history | answered | hschou | CC BY-SA 3.0 |