deleted 102 characters in body

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edited Jan 6, 2019 at 13:07

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This gives me an error that says too many arguments:

if [ $( file -b $i ) == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

This gives me an error that says too many arguments:

if [ $( file -b $i ) == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

This gives me an error that says too many arguments:

if [ $( file -b $i ) == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation?

deleted 2 characters in body

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edited Jan 15, 2017 at 14:20

muru

77.9k
16
212
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This gives me an error that says too many arguments:

if [ $( file -b $i ) ] == "directory" ]

if [ $( file -b $i ) == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

This gives me an error that says too many arguments:

if [ $( file -b $i ) ] == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

This gives me an error that says too many arguments:

if [ $( file -b $i ) == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

Tweeted twitter.com/StackUnix/status/820532013962850307

occurred Jan 15, 2017 at 7:24

OP's edit made the first point of the accepted answer invalid. Also, improved title

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edit approved Jan 15, 2017 at 5:10

Spikatrix

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Bash Why does itdoesn't the conditional work when I assign an output touse it directly without a variable?

This gives me an error that says too many arguments:

if [ $( file -b $i ) ] == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

Bash Why does it work when I assign an output to a variable?

This gives me an error that says too many arguments:

if [ $( file -b $i ) == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.

Why doesn't the conditional work when I use it directly without a variable?

This gives me an error that says too many arguments:

if [ $( file -b $i ) ] == "directory" ]

But when I tried this

name=$( file -b $i )
if [ name == "directory" ]

It seems to work just fine.

Can someone explain this or point out in the docs an explanation? I am new to bash but from the standpoint of other programming languages this doesn't make any sense.