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    Does this add anything to the prior answer, which AFAICT includes this idiom? echo $i is buggy, by the way -- if you have an argument passed as "*", you would instead have a list of filenames in the current directory emitted; should be echo "$i". Commented Oct 3, 2016 at 16:01
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    ...and printf '%s\n' "$i" is actually more correct than echo "$i" -- if your argument is -n, printf will print it, but echo may not (the POSIX specification for echo defines behavior as entirely undefined if the first argument is -n, or if any argument contains a backslash literal; moreover, some popular echo implementations defy black-letter POSIX by having -e or -E arguments have a behavior other than printing like strings on output). Commented Oct 3, 2016 at 16:02
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    The script does nothing. Pls explain! Commented Oct 3, 2016 at 19:17
  • @hschou, if it "does nothing", then you aren't passing it any arguments. Commented Oct 3, 2016 at 21:46
  • @hschou, I have updated the answer. The answer explains everything. Commented Oct 4, 2016 at 7:59