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"The philosophy of set -e is typically that it only exits upon uncaught errors. Here, the presence of || outside the subshell seems to tell the shell that the error inside the subshell is 'caught' and therefore set -e does not cause an exit after false." Yes, but the error inside the subshell is not reported. "false1" is not printed. It just masks the error, as if set -e was not in effect at all.

Jonas Berlin
– Jonas Berlin

2018-07-17 17:49:32 +00:00
Commented Jul 17, 2018 at 17:49
You appear to be talking about the case ( set -e; false ; true ) || echo false1. The subshell exits with the return code of the last command run. Since || suppresses the the exit after false, the last command executed in the subshell is true. Thus false1 is not printed because the subshell exits with return code zero.

John1024
– John1024

2018-07-17 18:40:16 +00:00
Commented Jul 17, 2018 at 18:40

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