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  • ok thank you! same question here: how would i load the search pattern from a file? Commented Jan 17, 2012 at 9:52
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    something like this, maybe ? pattern=cat /path/to/pattern; replacement=cat /path/to/replacement; find . -name "*.php" | xargs -n 1 sed -i -e "s/$pattern/$replacement/g" Commented Jan 17, 2012 at 10:04
  • thank you! the only problem remaining is that the pattern contains forward slashes which seem to be problematic in the regexp Commented Jan 17, 2012 at 10:06
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    you can use an other character than '/' in sed. For instance, sed -i -e "|$pattern|$replacement|g works well Commented Jan 17, 2012 at 10:15
  • thank you! now it runs without errors but it doesnt seem to replace anything. i guess the search pattern is not found. (although it is there). the search pattern contains all kind of characters including tabs, spaces, $, <, > etc. could that be the problem? Commented Jan 17, 2012 at 10:22