I need to write a script that will find files that contain a string in their name. If a file exists that is the same name but without that string, I want to remove the original file.

For example, if I am in a directory with the following files:

algomb
gomba
alb
algomba
alba

If the substring is gom then I would consider algomb, gomba, and algomba. Removing gom from each of those names I would check for the existance of alb, ba, and alba. Of those, alb and alba do exist, so I would remove algomb and algomba leaving just

alb
alba
gomba

in the directory when I'm done.

Here is what I tried:

#!/bin/bash
sz="gom"

talal=`find . -type f -name "*$sz*" -exec basename {} \;`
ossz=`find . -type f -exec basename {} \;`
c=`echo ${talal%%:*}${talal##*:}`

for c in ossz; do       
    if [ ! -d ]; then
        echo "This is a directory"  
    else    
        if [ -f ];
        then
            find .-type f -name "*$sz*" -exec basename {} \;  
        else
            echo ${talal%%:*}${talal##*:} 
        fi  
    fi
done

So this is works. This echo ${talal%%:*}${talal##*:} is give back the filename without "gom". But I cant compare these values with find . -type f -exec basename {} \; results.

Given that I can find the substrings, how can I test for the files and remove the appropriate ones?

I need to write a script that will find files that contain a string in their name. If a file exists that is the same name but without that string, I want to remove the original file.

For example, if I am in a directory with the following files:

algomb
gomba
alb
algomba
alba

If the substring is gom then I would consider algomb, gomba, and algomba. Removing gom from each of those names I would check for the existance of alb, ba, and alba. Of those, alb and alba do exist, so I would remove algomb and algomba leaving just

alb
alba
gomba

in the directory when I'm done.

Here is what I tried:

#!/bin/bash
sz="gom"

talal=`find . -type f -name "*$sz*" -exec basename {} \;`
ossz=`find . -type f -exec basename {} \;`
c=`echo ${talal%%:*}${talal##*:}`

for c in ossz; do       
    if [ ! -d ]; then
        echo "This is a directory"  
    else    
        if [ -f ];
        then
            find .-type f -name "*$sz*" -exec basename {} \;  
        else
            echo ${talal%%:*}${talal##*:} 
        fi  
    fi
done

So this is works. This echo ${talal%%:*}${talal##*:} is give back the filename without "gom". But I can't compare these values with find . -type f -exec basename {} \; results.

Given that I can find the substrings, how can I test for the files and remove the appropriate ones?

have some problem in Shell scripting. So I have to write a script that find every file in a directory with this string: "gom". So i found all of them. After I need to cut it off, and compare that the remaining filename is exist. If exist i need to remove the file that contains the string.

Example: there are 5 files: algomb, gomba, alb, algomba, alba.

I need to find the filenames with "gom". algomb, gomba, algomba. After it i need to cut the "gom". And a remaining filenames is exist I need to remove the file with "gom" string. So after the cutting "gom" there will be 5 files: alb, ba, alb, alba, alba So there are two files that is extist: alb, alba....I need to remove the following files: algomb, albomba. After it the will be 3 files: gomba, alb, alba.

Sorry for my bad english.

I can find, I can remove, but I cant compare the filenames.

Here's my code:

#!/bin/bash
sz="gom"

talal=`find . -type f -name "*$sz*" -exec basename {} \;`
ossz=`find . -type f -exec basename {} \;`
c=`echo ${talal%%:*}${talal##*:}`

for c in ossz; do       
if [ ! -d ]; then
    echo "This is a directory"  
else    
if [ -f ];
then
    find .-type f -name "*$sz*" -exec basename {} \;  
else    
    echo ${talal%%:*}${talal##*:} 
 
fi  
fi
done

So this is works. This echo ${talal%%:*}${talal##*:} is give back the filename without "gom". But I cant compare these values with find . -type f -exec basename {} \; results.

Sorry for my bad english. Can sombody help me?

Best regards, Richard

I need to write a script that will find files that contain a string in their name. If a file exists that is the same name but without that string, I want to remove the original file.

For example, if I am in a directory with the following files:

algomb
gomba
alb
algomba
alba

If the substring is gom then I would consider algomb, gomba, and algomba. Removing gom from each of those names I would check for the existance of alb, ba, and alba. Of those, alb and alba do exist, so I would remove algomb and algomba leaving just

alb
alba
gomba

in the directory when I'm done.

Here is what I tried:

#!/bin/bash
sz="gom"

talal=`find . -type f -name "*$sz*" -exec basename {} \;`
ossz=`find . -type f -exec basename {} \;`
c=`echo ${talal%%:*}${talal##*:}`

for c in ossz; do       
    if [ ! -d ]; then
        echo "This is a directory"  
    else    
        if [ -f ];
        then
            find .-type f -name "*$sz*" -exec basename {} \;  
        else
            echo ${talal%%:*}${talal##*:} 
        fi  
    fi
done

So this is works. This echo ${talal%%:*}${talal##*:} is give back the filename without "gom". But I cant compare these values with find . -type f -exec basename {} \; results.

Given that I can find the substrings, how can I test for the files and remove the appropriate ones?