You are using a little endian CPU, the 16 bit words hexdump is showing are byte swapped.

6 is the offset of the second dump line which is empty, your file containing only six bytes.

Use od -c to get the expected order:

$ od -c test.txt 
0000000   p   r   o   v   a  \n
0000006

You are using a little endian CPU, the 16 bit words hexdump is showing are byte swapped.

6 is the offset of the second dump line which is empty, your file containing only six bytes.

Use od -c or od -t x1 to get the expected order:

$ od -c test.txt 
0000000   p   r   o   v   a  \n
0000006
$ od -t x1 test.txt 
0000000 70 72 6f 76 61 0a
0000006

You are using a little endian CPU, the 16 bit words hexdump is showing are byte swapped.

Use od -c to get the expected order:

$ od -c test.txt 
0000000   p   r   o   v   a  \n
0000006

You are using a little endian CPU, the 16 bit words hexdump is showing are byte swapped.

6 is the offset of the second dump line which is empty, your file containing only six bytes.

Use od -c to get the expected order:

$ od -c test.txt 
0000000   p   r   o   v   a  \n
0000006