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Literal references of text elements should be placed in inline-code, not boldface
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AdminBee
AdminBee
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In this case, %.0s always prints one instance of character(s) preceding it, HH in this case. When you use {1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.

In this case, %.0s always prints one instance of character(s) preceding it, H in this case. When you use {1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.

In this case, %.0s always prints one instance of character(s) preceding it, H in this case. When you use {1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.

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edit approved Feb 27, 2023 at 14:32
Manuel Jordan
edit approved Feb 27, 2023 at 14:32
Manuel Jordan
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In this case, %.0s always prints one instance of character(s) preceding it, HH in this case. When you use {1..5000}{1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printfprintf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.

In this case, %.0s always prints one instance of character(s) preceding it, H in this case. When you use {1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.

In this case, %.0s always prints one instance of character(s) preceding it, H in this case. When you use {1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.

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KM.
KM.
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In this case, %.0s always prints one instance of character(s) preceding it, H in this case. When you use {1..5000}, the shell expands it and it becomes:

printf 'H%.0s' 1 2 3 4 ... 5000 > H.txt

i.e., the printf command now has 5000 arguments, and for each argument, you will get one H. These don't have to be sequential or numeric:

printf 'H%.0s' a bc fg 12 34

prints HHHHH -- i.e., the number of arguments, 5 in this case.

Note, the ellipses in the 1st example above aren't inserted literally, they're there to indicate a sequence or range.