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deleted 19 characters in body

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edited Feb 6, 2015 at 16:49

#!/bin/sh

EPOCH='jan 1 1970'
sum=''sum=0

for i in 00:03:34 00:00:35 00:12:34
do
  sum="$(date -u -d "$EPOCH $i" +%s) + $sum"
done
sum="$sum 0"
echo $sum|bc

date -u -d "jan 1 1970" +%s gives 0. So date -u -d "jan 1 1970 00:03:34" +%s gives 214 secs.

#!/bin/sh

EPOCH='jan 1 1970'
sum=''

for i in 00:03:34 00:00:35 00:12:34
do
  sum="$(date -u -d "$EPOCH $i" +%s) + $sum"
done
sum="$sum 0"
echo $sum|bc

date -u -d "jan 1 1970" +%s gives 0. So date -u -d "jan 1 1970 00:03:34" +%s gives 214 secs.

#!/bin/sh

EPOCH='jan 1 1970'
sum=0

for i in 00:03:34 00:00:35 00:12:34
do
  sum="$(date -u -d "$EPOCH $i" +%s) + $sum"
done
echo $sum|bc

date -u -d "jan 1 1970" +%s gives 0. So date -u -d "jan 1 1970 00:03:34" +%s gives 214 secs.

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answered Feb 6, 2015 at 14:08

Nizam Mohamed

#!/bin/sh

EPOCH='jan 1 1970'
sum=''

for i in 00:03:34 00:00:35 00:12:34
do
  sum="$(date -u -d "$EPOCH $i" +%s) + $sum"
done
sum="$sum 0"
echo $sum|bc

date -u -d "jan 1 1970" +%s gives 0. So date -u -d "jan 1 1970 00:03:34" +%s gives 214 secs.