Revisions to How to replace only the Nth occurrence of a pattern in a file?

deleted 1 character in body

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edited Jan 29, 2015 at 12:35

It's a lot easier done with perl.

To change the 3^rd occurrence:

perl -pe 's{is}{++$n == 3 ? "us" : "is"$&}ge'

To change every 3^rd occurrence:

perl -pe 's{is}{++$n % 3 ? $& : "us"}ge'

It's a lot easier done with perl:

perl -pe 's{is}{++$n == 3 ? "us" : "is"}ge'

It's a lot easier done with perl.

To change the 3^rd occurrence:

perl -pe 's{is}{++$n == 3 ? "us" : $&}ge'

To change every 3^rd occurrence:

perl -pe 's{is}{++$n % 3 ? $& : "us"}ge'

Rollback to Revision 1

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edited Jan 29, 2015 at 12:33

It's a lot easier done with perl:

perl -pe 's{\bis\bis}{++$n == 3 ? "us" : "is"}ge'

It's a lot easier done with perl:

perl -pe 's{\bis\b}{++$n == 3 ? "us" : "is"}ge'

It's a lot easier done with perl:

perl -pe 's{is}{++$n == 3 ? "us" : "is"}ge'

The first version was matching the "is" within "this"

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edited Jan 29, 2015 at 12:24

It's a lot easier done with perl:

perl -pe 's{is\bis\b}{++$n == 3 ? "us" : "is"}ge'

It's a lot easier done with perl:

perl -pe 's{is}{++$n == 3 ? "us" : "is"}ge'

It's a lot easier done with perl:

perl -pe 's{\bis\b}{++$n == 3 ? "us" : "is"}ge'

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answered Jan 29, 2015 at 11:52

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