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Aug 26, 2022 at 13:21 history edited Stéphane Chazelas CC BY-SA 4.0
missing -e (or --). Can't use `echo` for arbitrary data. awk can stop at the first match as well.
Mar 21, 2016 at 10:14 comment added glenn jackman Yes that's right.
Mar 21, 2016 at 7:05 comment added XXX It seems that this: awk '$0 ~ /foo/ { print $0 }' is actually equivalent to this: awk -v pattern=foo '$0 ~ pattern { print $0 }. In other words, the // brackets are not needed anymore at all, because pattern becomes a dynamic regexp. Is that right?
Mar 21, 2014 at 16:15 comment added glenn jackman Don't write /$0 ~ search/ -- leave out the slashes: $0 ~ search
Mar 21, 2014 at 15:57 comment added glenn jackman Please show the contents of $line -- do it in your question for proper formatting.
Mar 21, 2014 at 15:53 comment added branquito maybe it has something to do with the way $line is retrieved, pattern search is done on the output of whois $line, $line coming from file in a WHILE DO block.
Mar 21, 2014 at 15:42 comment added branquito yes I noticed, it needs to be set on BEGIN block to zero each time, as it serves as a switch. But interestingly I tried now script using $0 ~ pattern, and it does not work, however with /'"$1"'/ it does work!? :O
Mar 21, 2014 at 15:35 comment added glenn jackman I didn't note the removal of the BEGIN block: an unassigned variable is treated as 0 in a numeric context or the empty string otherwise. So, an unassigned variable will be false in if (p) ...
Mar 21, 2014 at 15:30 vote accept branquito
Mar 21, 2014 at 15:30 comment added branquito This is exactly what solves this in a way I wanted (1st example), because it keeps the semantics, which was my goal. Thanks.
Mar 21, 2014 at 15:16 history answered glenn jackman CC BY-SA 3.0