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Inserted a missing hyphen in "0-9". Then did a trivial rewording because it requires 6 chars to be changed 8-)

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I would modify your own solution. Instead of deleting any $1 that doesn't match the required regexp, use grep to filter them out:

awk '{print $1}' /tmp/test | grep -iE '^[a-z0-9]{12}$'

Another alternativeAlternatively in pure sed:

sed 's/^\([a-zA-Z09]\Z0-9]\{12\}\)[ \t]\+.*/\1/' /tmp/test

I would modify your own solution. Instead of deleting any $1 that doesn't match the required regexp, use grep to filter them out:

awk '{print $1}' /tmp/test | grep -iE '^[a-z0-9]{12}$'

Another alternative in pure sed:

sed 's/^\([a-zA-Z09]\{12\}\)[ \t]\+.*/\1/' /tmp/test

I would modify your own solution. Instead of deleting any $1 that doesn't match the required regexp, use grep to filter them out:

awk '{print $1}' /tmp/test | grep -iE '^[a-z0-9]{12}$'

Alternatively in pure sed:

sed 's/^\([a-zA-Z0-9]\{12\}\)[ \t]\+.*/\1/' /tmp/test

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answered Jan 26, 2014 at 15:30

I would modify your own solution. Instead of deleting any $1 that doesn't match the required regexp, use grep to filter them out:

awk '{print $1}' /tmp/test | grep -iE '^[a-z0-9]{12}$'

Another alternative in pure sed:

sed 's/^\([a-zA-Z09]\{12\}\)[ \t]\+.*/\1/' /tmp/test