easier way to flatten or merge php array than this? [duplicate]

Question

I have an array of arrays.

For example:

$array[] = array("1", "2", "3");
$array[] = array("5", "9", "ok");
$array[] = array("test", "ok", 8");

What is the easiest way of flattening/merging this to just one array?

Result should be:

$array = array("1", "2", "3", "5", "9", "ok", "test", "ok", "8");

Is there an easier/simpler way to get this result than doing the below?

$result = array();
foreach ($array as $subarray) {
  foreach ($subarray as $value) {
    array_push($result, $value);
  }
}

see here in3.php.net/manual/en/function.array-merge.php

Bajrang
– Bajrang

2012-02-06 07:47:53 +00:00
Commented Feb 6, 2012 at 7:47 — Bajrang
– Bajrang, Commented Feb 6, 2012 at 7:47

Juicy Scripter · Accepted Answer · 2018-08-20 17:50:48Z

14

Since PHP 5.6 you may use ... operator to provide arguments:

array_merge(...$array)

Old answer

As suggested, you may use array_merge for this. If you don't know how many values in your $array you may use something like this:

call_user_func_array('array_merge', $array);

edited Aug 20, 2018 at 17:50

answered Feb 6, 2012 at 7:50

Juicy Scripter

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2 Comments

Gogowitsch Over a year ago

Instead of the code above you can also write array_merge(...$array). The 3 dots need to be exactly like this. It's called the variadic functions operator.

Doro Over a year ago

array_merge($array1,...$array2); helped me out thanks.

nikc.org · Accepted Answer · 2012-02-06 07:46:57Z

4

array_merge would fit the bill.

$result = array_merge($array[1], $array[2], $array[3], ..., $array[N]);

Or if you insist on iteration:

$result = array();
foreach ($array as $nested) {
     $result = array_merge($result, $nested);
}

answered Feb 6, 2012 at 7:46

nikc.org

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