I want to post a php variable from a form

Question

I have a php variable "echo $id". Now I want to use the $_POST method to post the variable. I just want to know how to do this for a variable because $_POST[$id] does not work?

I'm afraid you'll have to get acquainted with some concepts first. — Michael Krelin - hacker
– Michael Krelin - hacker, Commented Dec 17, 2011 at 13:34
What do you mean by posting the variable? $_POST gets data out of a form into a variable. And it's not a method, $_POST is a variable itself. — Johan
– Johan, Commented Dec 17, 2011 at 13:35

Madara's Ghost · Accepted Answer · 2011-12-17 13:37:29Z

2

I think you are misunderstanding a basic concept here.

The $_POST super global is used to receive input (in the form of a POST request) from the user. While it is possible to set variables in it, you shouldn't.

answered Dec 17, 2011 at 13:37

Madara's Ghost

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Niet the Dark Absol · Accepted Answer · 2011-12-17 13:36:38Z

Your question does not make sense. If you have an HTML form:

<form action="" method="post">
    <input type="text" name="something" />
    <input type="submit" value="Submit" />
</form>

Then you get the variable $_POST['something'] with whatever the user typed in the text box.

On its own, $_POST is just a variable like any other. You can assign to it $_POST['test'] = 123;, you can delete from it unset($_POST['test']);, you can even make it something other than an array $_POST = "Hello, world";, it just happens to be pre-populated with form data, if any.

H Bellamy · Accepted Answer · 2011-12-17 13:35:48Z

0

With the method $_POST you must be posting to something.

My suggestion to you is to create a form, then have the form going to the file you wish to post to:

So something like this:

echo '<form action  = "fileToPostTo.php" method = "post">
<input type = "text" hidden value = "'.$id.'" />
</form>';

And then submit the form when the document loads through jquery or javascript.

answered Dec 17, 2011 at 13:35

H Bellamy

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Comments

Jazi · Accepted Answer · 2011-12-17 13:39:58Z

0

You can do it by $_POST['id'] = $id (then You will have it in $_POST['id'] variable (but You shouldn't do it :P).

Or You can send $id by form. Like example:

<form action="/pageToPOST.php" method="post">
  <input type="text" value="<?=$id ?>" name="id" />
  <input type="submit" name="" value="submit it!" />
</form>

And You'll have $_POST['id'] on http://yourdomainname.com/pageToPOST.php page

edited Dec 17, 2011 at 13:39

answered Dec 17, 2011 at 13:34

Jazi

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SANR1103219 · Accepted Answer · 2011-12-17 14:04:24Z

you can get and pass the value without page load and form.

 <input type="text" name="something" id="something" />
 <input type="button" value="ok" onclick="value();"/>
 function value()
 {
 var something=$("#something").val();
 var dataparam="oper=show&something="+something;
  $.ajax({
      type:"post",
      url:"yourphpname.pnp",//this is very important.
      data:dataparam,
      success:function(data)
   {
   alert(data);
   }
   });
    }
     $oper =(isset( $_REQUEST['oper'])) ?  $_REQUEST['oper'] : '';
          if($oper == "show" and $oper != '')
          {
         $something=$_REQUEST['something']
         echo $something;
         }

Frank · Accepted Answer · 2011-12-17 15:50:13Z

0

what you want to do is assign a value submitted to your script using the POST method, to your $id variable. Something like:

$id = $_POST['id'];

answered Dec 17, 2011 at 15:50

Frank

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