The function:
def thefunction():
exec("x = 'text'")
return x
print(thefunction())
and it doesnt work... this is for python 3
2 Answers
Give it a dict as a storage for variables.
def thefunction():
vars = {}
exec("x = 'text'", vars)
return vars['x']
print(thefunction())
In any case, read the documentation and warnings about exec.
Comments
you need to pass in your locals or it will only be local to that ...
def thefunction():
my_locals = locals()
exec("x = 'text'",globals(),my_locals)
return my_locals['x']
print(thefunction())
you can make it a little safer by sending in an isolated environment... but the bottom line is that its not safe to exec untrusted input
7 Comments
Mechanic Pig
It gives me
NameError: name 'x' is not defined, in Python 3.10.8. It is valid to use globals() as the third argument, which writes the result to the global variable, then retrieves x from the global variable and returns it.
Joran Beasley
I just double checked ... it works perfectly in my interpretter ... (I did have globals and locals swapped earlier .... but that should not have resulted in a nameerror)
Mechanic Pig
Did you delete
x from the global variable and retest it? The local variable of the function is now implemented using an array. The document of exec never guarantees that it can work properly in the function...
juanpa.arrivillaga
@JoranBeasley you sure you are using Python 3?
juanpa.arrivillaga
@MechanicPig that's not true. It just won't modify the function's local namespace. But you can pass in your own namespace and it should work
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execdocumentation?