Is there any way to raise multiple exceptions in python? In the following example, only the first exception is raised.
l = [0]
try:
1 / 0
except ZeroDivisionError as e:
raise Exception('zero division error') from e
try:
l[1]
except IndexError as e:
raise Exception('Index out of range') from e
Is there any other way?
Once an exception is raised and not catched, the execution of your program will stop. Hence, only one exception can be launched in such a simple script.
If you really want your program to raise multiple exceptions, you could however create a custom Exception representing multiple exceptions and launch it inside an except block. Example:
class ZeroDivAndIndexException(Exception):
"""Exception for Zero division and Index Out Of Bounds."""
I = [0]
try:
1 / I[0]
except ZeroDivisionError as e:
try:
I[1]
# Here you may raise Exception('zero division error')
except IndexError as e2:
raise ZeroDivAndIndexException()
# Here you may raise Exception('zero division error') with raise Exception('zero division error') from e you will see an issueHere my solution a bit long but seems to work :
class CustomError(Exception):
pass
l = [0]
exeps = []
try:
1 / 0
except ZeroDivisionError as e:
exeps.append(e)
try:
l[1]
except IndexError as e:
exeps.append(e)
if len(exeps)!=0:
[print(i.args[0]) for i in exeps]
raise CustomError("Multiple errors !!")
try:
pass
except AttributeError:
pass
except IndexError:
pass
