How to Combine more than 4 Arrays in Swift?

Question

I have a few separate arrays that I am trying to combine. When I have more than 4 arrays that I try to combine, it does not build and only gives the error The compiler is unable to type-check this expression in reasonable time; try breaking up the expression into distinct sub-expressions. I have tried it multiple different ways and am sure that it is only when I attempt to combine more than 4 arrays. Here is how I combine them:

For example let's say these are my arrays:

var a = [1, 2, 3, 4]
var b = [4, 6, 8, 10]
var c = [2, 4, 6, 8]
var d = [3, 6, 9, 12]
var e = [1, 3, 5, 7]

Then I combine them and sort like this:

This works:

(a+b+c+d).sorted { $0.name < $1.name }

But this does not and causes the build to fail:

(a+b+c+d+e).sorted { $0.name < $1.name }

Is there a different way that I should go about combining these arrays to support the combination of more than 4?

Where are you doing this stuff? In the body of a SwiftUI view, or...? — West1
– West1, Commented May 29, 2021 at 21:52
Best to create Chain5 and submit for inclusion in Algorithms. github.com/apple/swift-algorithms/blob/main/Guides/Chain.md — user652038
– user652038, Commented May 29, 2021 at 22:09

workingdog support Ukraine · Accepted Answer · 2021-05-29 22:37:38Z

the following works well for me on macos 11.4, xcode 12.5, target ios 14.5 and macCatalyst 11.3. Show us exactly how you are using the code.

import SwiftUI

@main
struct TestErrorApp: App {
    var body: some Scene {
        WindowGroup {
            ContentView()
        }
    }
}
struct ContentView: View {
    var a = [1, 2, 3, 4]
    var b = [4, 6, 8, 10]
    var c = [2, 4, 6, 8]
    var d = [3, 6, 9, 12]
    var e = [1, 3, 5, 7]
    var f = [4, 6, 8, 10]
    var g = [1, 3, 5, 7]
    var h = [2, 4, 6, 8]
    
    var body: some View {
        Text("array combination").onAppear {
            let arr = (a+b+c+d+e+f+g+h).sorted { $0 < $1 }
            print("----> arr: \(arr)")
        }
}
}

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