Array-in-struct initialization in C and C++

Question

I have the following code in C that works just fine

typedef struct { float m[16]; } matrix;

matrix getProjectionMatrix(int w, int h)
{
  float fov_y = 1;
  float tanFov = tanf( fov_y * 0.5f );
  float aspect = (float)w / (float)h;
  float near = 1.0f;
  float far = 1000.0f;

  return (matrix) { .m = {
    [0] = 1.0f / (aspect * tanFov ),
    [5] = 1.0f / tanFov,
    [10] = -1.f,
    [11] = -1.0f,
    [14] = -(2.0f * near)
  }};
}

When I try to use it in C++ I get this compiler error: error C2143: syntax error: missing ']' before 'constant'

Why so and what's the easiest way to port the code to C++?

Designated Initializers were added in the C++ 20 Standard revision, but I don't think that they allow array initializing like that. Does adding a constructor make any sense? — user4581301
– user4581301, Commented Jul 11, 2020 at 19:35
Do you need to compile this file as C++? Perhaps you can compile it as C, leaving the rest of your app as C++. I do this for certain parts of my codebase and it works fine. — catnip
– catnip, Commented Jul 11, 2020 at 19:40
Have a look at this answer: stackoverflow.com/a/13562974/260313 — rturrado
– rturrado, Commented Jul 11, 2020 at 19:43
@rturrado so it's a duplicate :( sorry, I searched but did not see that one — Anton Duzenko
– Anton Duzenko, Commented Jul 11, 2020 at 19:45
@Anton Duzenko no probs, you always get some new and interesting comments and answers 😊 — rturrado
– rturrado, Commented Jul 11, 2020 at 19:47

dbush · Accepted Answer · 2020-07-11 19:36:00Z

6

You're attempting to use a designated initializer which is allowed in C but not C++.

You'll need to explicitly initialize the individual members:

  return (matrix) { {
    1.0f / (aspect * tanFov ),
    0, 0, 0, 0,
    1.0f / tanFov,
    0, 0, 0, 0,
    -1.f,
    -1.0f,
    0, 0,
    -(2.0f * near),
    0
  }};

answered Jul 11, 2020 at 19:36

dbush

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