Convert this curl command to Python 3

Question

How can I send this curl out using Python? I did find similar requests, but cannot adapt my code to suite the query I have also tried using pycurl, following this example but without luck.

$ curl -v -X GET  -H "Accept: text/csv" -H "Authorization: Basic YW5kcmVhLmJvdHRpQHdzcC5jb206OWY5N2E5YTY2ZWU1MTMxZjdmNjk4MDcwZTFkODEwMjU0M2I0NTg1ZA==" "https://epc.opendatacommunities.org/api/v1/domestic/search"

Thanks

Possible duplicate of adding header to python requests module — Diptangsu Goswami
– Diptangsu Goswami, Commented Sep 4, 2019 at 10:45

Bob · Accepted Answer · 2019-09-04 10:42:45Z

2

If you are using the Python Requests package the following code snippet should work:

import requests

headers = {
    'Accept': 'text/csv',
    'Authorization': 'Basic YW5kcmVhLmJvdHRpQHdzcC5jb206OWY5N2E5YTY2ZWU1MTMxZjdmNjk4MDcwZTFkODEwMjU0M2I0NTg1ZA==',
}

response = requests.get('https://epc.opendatacommunities.org/api/v1/domestic/search', headers=headers)

response.status_code  # 200
response.text # "lmk-key,address1,address2,address3,postcode,buildi ..."

(Note: I used the https://curl.trillworks.com/ website to automatically make the conversion)

answered Sep 4, 2019 at 10:42

Bob

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