Get byte from number problem

Question

I have test array of hex(radix 16) numbers

var numbers = ["01","02","a1"];

and I convert them to int(radix 10) by using

var num = parseInt(temp.join(''), 16);

where temp is an number in the array of numbers.

I extract byte like

( num >> (8*index_byte) & 0xFF)

but I dont get value like "03", problem is that I get just 3. How to get like "01" not 1 or "02" not 2 ?

rmflow · Accepted Answer · 2011-03-30 08:04:17Z

1

Something like:

num = 1;
if (String(num).length < 2)
{
    num = "0" + num;
}

answered Mar 30, 2011 at 8:04

rmflow

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1 Comment

Bakudan Over a year ago

var num = 1; num = num.toString().length < 2 ? "0" + num : num; for simple comparisons you can use ternary (it`s said that it will produce faster code, not very sure, give it a try)

user447356 · Accepted Answer · 2011-03-30 08:04:03Z

1

03 is 3 by all means.

Your only option is padding the number yourself:

var byte = "0" + (num >> (8 * index_byte) & 0xFF);

answered Mar 30, 2011 at 8:04

user447356

Comments

Jonas Elfström · Accepted Answer · 2011-03-30 08:06:25Z

0

You could use String.js from jsxt.

var fnumber = '%02d'.sprintf( num>>(8*index_byte) & 0xFF );

answered Mar 30, 2011 at 8:06

Jonas Elfström

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