PHP generate arrays in loop

Question

I have these loop statement to generate arrays labeled with z variable. array will be sent to ajax to be displayed in HTML page.

    for($z=0;$z<5;$z++){    
        $billsum = $bills['amount'];
         $bill['$z'] = [$billsum];      
    }

How can I generate arrays such as $bill0,$bill1,$bill2,$bill3,...etc

remove the ' around $z: $bill[$z] = $billsum; (and the [] - or do you really want another nested array in there?) — Jeff
– Jeff, Commented Oct 25, 2018 at 15:34
since you accepted an answer below (which is correct) I just wanted to tell you, that it's a very bad idea to have variables named $bill0, $bill1, ... This is what arrays are for! — Jeff
– Jeff, Commented Oct 25, 2018 at 16:03
it's far better and more practical to have an array $bills that contains each bill in $bill[0], $bill[1],... (or maybe you want an array with only billsums, then call it $billsums[1], .. — Jeff
– Jeff, Commented Oct 25, 2018 at 16:06

Alex · Accepted Answer · 2018-10-25 15:36:08Z

2

$z shouldn't be inside quotes.

for($z=0;$z<5;$z++){    
        $billsum = $bills['amount'];
        $bill[$z] = [$billsum];      
}

answered Oct 25, 2018 at 15:36

Alex

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3 Comments

PHP Notice: Undefined variable: bill0

What line is that?

I'm sending the array back to ajax. the correct way is marked already thx

nice_dev · Accepted Answer · 2018-10-25 15:41:16Z

1

for($z=0;$z<5;$z++){    
        $billsum = $bills['amount'];
        ${'bill'.$z} = [$billsum];      
}

So, now you will have arrays like $bill0,$bill1,$bill2,$bill3...

answered Oct 25, 2018 at 15:41

nice_dev

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