Show nested array in consecutive lines in python [duplicate]

Question

This is my python code:

d = []
for x in range(5):
d.append(["O"] * 5)
print d

and output is:

[['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O']]

but I want the output as follows:

['O', 'O', 'O', 'O', 'O']
['O', 'O', 'O', 'O', 'O']
['O', 'O', 'O', 'O', 'O']
['O', 'O', 'O', 'O', 'O']
['O', 'O', 'O', 'O', 'O']

Eventually like this:

O O O O O
O O O O O
O O O O O
O O O O O
O O O O O

You can make it simplest with numpy: import numpy as np and d=np.zeros((5,5)) — Alessandro Peca
– Alessandro Peca, Commented Oct 7, 2018 at 8:10

vash_the_stampede · Accepted Answer · 2018-10-07 08:05:35Z

1

The first one happens like this, if you just print(d) you will print the entire list but by looking at the desired output, we can tell we only want one sublist per line. So we loop through d and print each sublist i on its own line

d = []
for i in range(5):
    d.append(['0']*5)

for i in d:
    print(i)

['0', '0', '0', '0', '0']
['0', '0', '0', '0', '0']
['0', '0', '0', '0', '0']
['0', '0', '0', '0', '0']
['0', '0', '0', '0', '0']

For the second part its the same concept except we use * to unpack the items.

for i in d:
    print(*i)

answered Oct 7, 2018 at 8:05

vash_the_stampede

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2 Comments

omid Over a year ago

I write this code on tutorialspoint.com/execute_python_online.php : d = [] for x in range(5): d.append(["O"] * 5) for i in d: print (*i) but i receive SyntaxError for *i

vash_the_stampede Over a year ago

@omid it probably has to do with the online compiler

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