results=[key for key, value in adictionary if str(key).startswith('target')
and value > 0 ]
What am I trying to do here is select all the keys if the key in dictionary that beginswith target and its value is greater than 0. But looks there's a problem with this, help me~
results=[key for key, value in adictionary.items() if str(key).startswith('target')
and value > 0 ]
Missing items() ior iteritems() to your dict access. iteritems will not create a temp list which could be slightly faster.
results=[key for key, value in adictionary.iteritems() if str(key).startswith('target')
and value > 0 ]
You need to use the items() method to get both key and value.
[key for key, value in adictionary.items() if str(key).startswith('target') and value > 0]
startswith() is slower than slicing
I would do:
results=[k for k,v in adictionary.iteritems()
if (k[0:7]=='target')==True==(v>0)]
I'd use the iteritems() method of the dictionary. It returns an interator rather than generating a full list like the items() method does.
results = [key for key, value in adictionary.iteritems() if str(key).startswith('target') and value > 0]
