JavaScript regex for username validation

Question

I tried with many patters for username in my Angular5 application. But didn't get a suitable solution for my requirement.

The Rules are

Minimum 6 characters
Only numbers are not allowed at least one character should be there
No special characters allowed except _
No space allowed
Character only is allowed

I tried with /^[a-zA-Z0-9]+([_]?[a-zA-Z0-9])*$/

/^[a-zA-Z0-9][a-zA-Z0-9_]*[a-zA-Z0-9](?<![_\s\-]{6,}.*)$/

I have handled minimum number separately because I want to display a message for that case. My issue is only number case is not able to validate. @VicJordan Allan — Vimal
– Vimal, Commented Jun 1, 2018 at 1:12
Is this fine? "/^[a-zA-Z0-9][a-zA-Z0-9_]*[a-zA-Z0-9](?<![-?\d+\.?\d*$]{6,}.*)$/" — Vimal
– Vimal, Commented Jun 1, 2018 at 1:20

AHT · Accepted Answer · 2018-06-01 02:36:42Z

10

You can try this regex:

^[a-zA-Z0-9_]{5,}[a-zA-Z]+[0-9]*$

[a-zA-Z0-9_]{5,} to match at least five alphanumerics and the underscore
[a-zA-Z]+ to have at least one letter
[0-9]* to match zero to any occurrence of the given numbers range

Hope this helps.

answered Jun 1, 2018 at 2:36

AHT

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Comments

Allan · Accepted Answer · 2018-06-01 01:42:35Z

2

You can use the following regex:

^(?=[a-z_\d]*[a-z])[a-z_\d]{6,}$

in case insensitive mode as tested on regex101: demo

Explanations:

^ anchor for the beginning of the string
$ anchor for the end of the string
(?=[a-z_\d]*[a-z]) to force the presence of at least one letter
[a-z_\d]{6,} implement the at least 6 char constraint

answered Jun 1, 2018 at 1:42

Allan

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Comments

Vimal · Accepted Answer · 2018-06-01 01:22:36Z

-1

Yes this is fine for me. Thanks./^[a-zA-Z0-9][a-zA-Z0-9_]*[a-zA-Z0-9](?<![-?\d+\.?\d*$]{6,}.*)$/

answered Jun 1, 2018 at 1:22

Vimal

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1 Comment

Vimal Over a year ago

No fail for this. "5mm656565v5". :(

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