Bash equivalent of preg_replace()

Question

I have to remove the extension from a filename, and I was using this:

preg_replace('/\\.[^.\\s]{3,4}$/', '', $filename)

I want to know what is the sed equivalent of this. My current approach is this:

$(echo $filename | cut -f 1 -d '.')

but it does not work all the time.

and

Do regex and sed have same expressions for matching and the syntax is different or the expressions also change?

For regex in bash with sed stackoverflow.com/questions/14072592/… — JustOnUnderMillions
– JustOnUnderMillions, Commented Apr 5, 2017 at 11:49
Extract filename & extention stackoverflow.com/questions/965053/… — JustOnUnderMillions
– JustOnUnderMillions, Commented Apr 5, 2017 at 11:51
Possible duplicate of How can I change the extension name in a string with bash? — l'L'l
– l'L'l, Commented Apr 5, 2017 at 12:03

Mario · Accepted Answer · 2017-04-05 12:07:55Z

2

Here are some examples of cutting text with bash...

FileName="/var/www/html/index.html"
echo "${FileName}"
/var/www/html/index.html

echo "${FileName%/*}"
/var/www/html

echo "${FileName##*/}"
index.html

TmpVal=$(echo "${FileName%.*}")
echo "${TmpVal##*/}"
index

Description...

${variable%pattern} removes first pattern on the right
${variable%%pattern} removes last pattern on the right
${variable#pattern} removes first pattern on the left
${variable##pattern} removes last pattern on the left

answered Apr 5, 2017 at 12:07

Mario

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