Let's say I have a bash script that calls a node script. I've tried to do it like this:
b.sh file:
#!/bin/bash
v=$(node app.js)
echo "$v"
app.js file:
#!/usr/bin/env node
function f() {
return "test";
}
return f();
How do I access the value returned by the node script ("test") from my bash script ?
@Daniel Lizik gave an good answer (now deleted) for the part: how to output the value, e.g. using his answer:
#!/usr/bin/env node
function f() {
return "test";
}
console.log(f())
And for the part how to capture the value in bash, do exactly as in your question:
#!/bin/bash
val=$(node app.js)
echo "node returned: $val"
the above prints:
node returned: test
bash level, for example val=$(node app.js | grep 'test') for get only lines containing the test string and so on... Zilion possibilities..You can write output to the stdout with process.stdout.write
b.sh file:
#!/bin/bash
v=$(node app.js)
echo "$v"
app.js file:
#!/usr/bin/env node
function f() {
return "test";
}
process.stdout.write(f());
testis returned to themainand it isn't printed to the output, so here is nothing to capture... You need output the returned value...