How to add jquery variable data in php statement? [duplicate]

Question

i am getting stuck on this problem. i want to do using jquery

window.newdatevalue = '<?php echo date("Y-m-d") ?>';// this date is dynamic

var newdate = window.newdatevalue;

console.log(newdate); // when i print this it give me right result -2017-02-06 

var finaldate = "<?php echo date('d/M/y',strtotime('"+newdate+"'))?>";

console.log(finaldate); // but when i print this it give me wrong result 01/Jan/70

Can anyone help me what i am doing wrong

try change finaldate format to "Y-m-d" [ echo date("Y-m-d",strtotime('"+newdate+"')) ] — SarangaR
– SarangaR, Commented Feb 6, 2017 at 5:27
PHP executes on the server, then the server sends the page to the browser, and javascript runs. You can't just inject a javascript variable in PHP, it's too late — adeneo
– adeneo, Commented Feb 6, 2017 at 5:30
for change date format see stackoverflow.com/questions/33299687/… — Bharat Dangar
– Bharat Dangar, Commented Feb 6, 2017 at 5:37
I think, you are misunderstanding some principle of server side programming any way I think you hope following answer [ echo date("d/m/Y",strtotime(date('Y-m-d'))); ] or [ echo date('d/m/Y'); ] — SarangaR
– SarangaR, Commented Feb 6, 2017 at 5:38

Naincy · Accepted Answer · 2017-02-06 05:30:00Z

0

Can try this. It might help you.

window.newdatevalue = '<?php echo date("d-m-Y", strtotime(date("Y-m-d"))); ?>'

console.log(window.newdatevalue);

answered Feb 6, 2017 at 5:30

Naincy

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4 Comments

kunal Over a year ago

where is $originalDate;

Naincy Over a year ago

updated my answer

kunal Over a year ago

i have different date in different day. So i want to place variable in strtotime

Naincy Over a year ago

what you mean in above... please specify more clearly

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