Deserialize array in JSON into class/object

Question

I'm trying to store JSON data into a class. I could deserialize my otherJSON string into class by: var ser = JsonConvert.DeserializeObject<ClsResult>(myJSON); before I got stuck with array.

    {
      \"Test\": [{
         \"FirstBool\":1, 
         \"aString\":\"hello\"
      }]
    }

This is my class for JSON:

public class Test
{
    [JsonProperty("FirstBool")]
    public bool FirstBool { get; set; }

    [JsonProperty("aString")]
    public string aString { get; set; }
}      

public class ResultObject
{
        [JsonProperty("Test")]
        public List<Test> Test { get; set; }
}

How I deserialize my non-array JSON:

var ser = JsonConvert.DeserializeObject<ResultObject>(myJSON);

What changes do I need to make it work again?

Are you sure FirstBool should be a bool? It's an int in the JSON. — Equalsk
– Equalsk, Commented Jan 25, 2017 at 10:43

mrogal.ski · Accepted Answer · 2017-01-25 12:09:51Z

Edited answer

Your json string as I've noticed later contains object named Test which is basically an array of objects ( object[] ).

As you can see from the json string :

{ "Test": [{ "FirstBool" : 1, "aString" : "hello" }] }

[ means that json object begins an array type and ] means that json object ended an array type.

{ means that json object begins an object type and } means that json object ended an object type.

Which in your case will require to make kind of a custom deserializer using existing methods from Newtonsoft.Json library.

Example for the Test object could be :

JObject obj = JObject.Parse(jsonString);
// now your obj contains field named "Test" that is of type object[]
// to retrieve informations you have to select "Test" token
JToken testToken = obj.SelectToken("Test");
// your token contains now something like " [{ "FirstBool" : 1, "aString" : "hello" }]"
// which basically is an array
// meaning that you have to iterate through this
foreach(var child in token.Children())
{
    // and convert it to a Test object
    Test test = JsonConvert.DeserializeObject<Test>(child.ToString());
    // test now is fully deserialized object
}

By you recommendation, should I change public List<Test> Test { get; set; } to public Test Test { get; set; } as well?
@user7399041 Sorry my bad. I haven't read your sample json string. Now this should work as intended.
Thanks a lot for the well explained edited answer :) Works really well.

galister · Accepted Answer · 2017-01-25 10:42:25Z

0

Deserialize it as a list:

JsonConvert.DeserializeObject<List<Test>>(json);

...instead of a wrapper object.

answered Jan 25, 2017 at 10:42

galister

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2 Comments

user7399041 Over a year ago

Should I change public List<Test> Test { get; set; } to public Test Test { get; set; } as well?

galister Over a year ago

You don't need the ResultObject at all! It's just a wrapper right now, let JsonConvert handle it for you.

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