C#: Deserialize JSON

Question

I have a problem with Deserializing JSON

This is my JSON file

{
  "api_result": 1,
  "api_result_msg": "OK",
  "api_data": {
    "api_basic": {
      "api_nickname": "David",
    },
    "api_p_bgm_id": 112,
    "api_parallel_quest_count": 5
  }
}

The matching class(generated by special paste in visual studio):

public class Rootobject
{
    public int api_result { get; set; }
    public string api_result_msg { get; set; }
    public Api_Data api_data { get; set; }
}

public class Api_Data
{
    public Api_Basic api_basic { get; set; }
    public int api_p_bgm_id { get; set; }
    public int api_parallel_quest_count { get; set; }
}

public class Api_Basic
{
    public string api_nickname { get; set; }
}

And my code:

    string JJ = "{\"api_result\":1,\"api_result_msg\":\"OK\",\"api_data\":{\"api_basic\":{\"api_nickname\":\"David\"},\"api_p_bgm_id\":112,\"api_parallel_quest_count\":5}}";
    Rootobject result = JsonConvert.DeserializeObject<Rootobject>(JJ);
    Api_Basic nickname = JsonConvert.DeserializeObject<Api_Basic>(JJ);

    Console.WriteLine("result:" + result.api_result_msg);
    Console.WriteLine("nickname:" + nickname.api_nickname);

The output:

result:OK <---success
nickname: <---fail

I tried:

Rootobject nickname = JsonConvert.DeserializeObject<Rootobject>(JJ);
Console.WriteLine(nickname.api_basic.api_nickname);

But this doesn't work.

What am I doing wrong?

In your second sample it should be nickname.api_data.api_basic.api_nickname — Ulugbek Umirov
– Ulugbek Umirov, Commented Sep 2, 2016 at 14:34
Your JSON is not valid. Remove the comma after "api_nickname": "David" — Ferhat Sayan
– Ferhat Sayan, Commented Sep 2, 2016 at 14:35
What do you mean by doesn't work ? Does it throw a runtime exception? Does it not compile? Please be more clear and specific — Matias Cicero
– Matias Cicero, Commented Sep 2, 2016 at 14:36
omg, you solve my problem extremely quick. thank you Ulugbek Umirov Ferhat Sayan, Matias Cicero, Alberto — A. Chung
– A. Chung, Commented Sep 2, 2016 at 14:44

Alberto · Accepted Answer · 2016-09-02 14:36:19Z

3

Why performing the deserialization two times?

You only need the first object:

string JJ = "{\"api_result\":1,\"api_result_msg\":\"OK\",\"api_data\":{\"api_basic\":{\"api_nickname\":\"David\"},\"api_p_bgm_id\":112,\"api_parallel_quest_count\":5}}";
Rootobject result = JsonConvert.DeserializeObject<Rootobject>(JJ);

Console.WriteLine("result:" + result.api_result_msg);
Console.WriteLine("nickname:" + result.api_data.api_basic.api_nickname);

answered Sep 2, 2016 at 14:36

Alberto

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