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I have something in a text file that looks like '%r'%XXXX, where the XXXX represents some name at the end. Examples include '%r'%addR or '%r'%removeA. I can match these patterns using regex '%r'%\w+. What I would like to replace this with is '{!r}'.format(XXXX). Note that the name has to stay the same in the replace so I'd get '{!r}.format(addR) or '{!r}.format(removeA). Is there a way to replace parts of the matched string in this way while retaining the unknown variable name pulled out with \w+ in the regex search?

I'm specifically looking for a solution using the find and replace features in Notepad++.

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  • Is '%r'%XXXX an entire line? If not, describe the context. Does '%r'%XXXX appear more than once in a line? Commented Apr 5, 2016 at 14:36
  • You need capturing groups + backreferences. Commented Apr 5, 2016 at 14:36
  • @Smandoli The text can be located inside a line and more than one may be in a line at a time. Commented Apr 5, 2016 at 14:37

2 Answers 2

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You can use

'%r'%(\w+)

and replace with '{!r}.format\(\1\)

The '%r'%(\w+) pattern contains a pair of unescaped parentheses that create a capturing group. Inside the replacement pattern, we use a \1 backreference to restore that value.

NOTE: The ( and ) in the replacement must be escaped because otherwise they are treated as Boost conditional replacement pattern functional characters.

See more on capturing groups and backreferences.

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Search on:

'%r'%(XXXX)

Replace with:

Whatever You like \1

\1 will match the first set of grouping parentheses.

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