Javascript hexadecimal number validation using regular expression

Question

My function should return true if the hexa number is valid using regular expressions note: hexadecimal numbers may contain a point(.) for decimals (example: 2E6.A3)

Hexadecimal: 0 1 2 3 4 5 6 7 8 9 A B C D E F

I gave examples on my main()

function returnHexaNumber(string) {
    var regExp = /^[-+]?[0-9A-Fa-f]+\.[0-9A-Fa-f]?$/
    return (isAString(string) && regExp.test(string))
}
function main() {
    alert("true : " + returnHexaNumber('2E6'))
    alert("true : " + returnHexaNumber('2E6.A3'))
    alert("false : " + returnHexaNumber('ZZZ'))
    alert("false : " + returnHexaNumber(''))
    alert("false : " + returnHexaNumber(0))
    alert("false : " + returnHexaNumber('10'))
}

What's the issue/problem/question? Also, your snippet doesn't do anything probably because you're not calling main. — user663031
– user663031, Commented Mar 16, 2016 at 17:46

Jonathan.Brink · Accepted Answer · 2016-03-16 17:44:34Z

I made \. optional with \.? and the second [0-9A-Fa-f] take multiple characters by adding *.

function returnHexaNumber(s) {
    var regExp = /^[-+]?[0-9A-Fa-f]+\.?[0-9A-Fa-f]*?$/;
    return (typeof s === 'string' && regExp.test(s));
}
function main() {
    console.log("true : " + returnHexaNumber('2E6'));
    console.log("true : " + returnHexaNumber('2E6.A3'));
    console.log("false : " + returnHexaNumber('ZZZ'));
    console.log("false : " + returnHexaNumber(''));
    console.log("false : " + returnHexaNumber(0));
    console.log("true : " + returnHexaNumber('10'));
}

main();

Shouldn't '10' return true? I switched the last test.

JSBin: http://jsbin.com/veyusokowu/edit?js,console

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