Generate a list of random string of fixed length in python [duplicate]

Question

I need to generate a list which will have random alphanumeric string of fixed length. It will be something like: list = ['ag5','5b9','c85'] I can make the list with random numbers, but I can't work out to make strings which will have both numbers and letters.The list will have fixed length(say 100 item). I am using python 3.

Answer 1

To obtain the set of alphanumeric characters you can combine constants from the string module. Then you can use random.choice() in a list comprehension to generate the list:

from random import choice
from string import ascii_lowercase, digits

chars = ascii_lowercase + digits
lst = [''.join(choice(chars) for _ in range(2)) for _ in range(100)]
print(lst)

Answer 2

Since you need every single string to have both a letter and a number, we need to do a little more work than usual. We can either keep generating random words and only accept the ones which satisfy our constraint, or we can build a collection of characters that satisfies the constraint by construction.

from random import choice, shuffle
from string import digits, ascii_lowercase

def gen_word(N, min_N_digits, min_N_lower):
    choose_from = [digits]*min_N_dig + [ascii_lowercase]*min_N_low
    choose_from.extend([digits + ascii_lowercase] * (N-min_N_low-min_N_dig))
    chars = [choice(bet) for bet in choose_from]
    shuffle(chars)
    return ''.join(chars)

def gen_word_rejection(N, min_N_digits, min_N_lower):
    bet = digits + ascii_lowercase
    while True:
        word = ''.join([choice(bet) for i in range(N)])
        if (sum(c.isdigit() for c in word) >= min_N_digits and
            sum(c.islower() for c in word) >= min_N_lower):
            return word

which gives me

>>> [gen_word(3, 1, 1) for i in range(5)]
['mb6', 'g4b', 'y5g', '28p', 'ki2']
>>> [gen_word_rejection(3, 1, 1) for i in range(5)]
['y37', 'dr0', 'w1z', 'h2a', 'i6r']

All of which have at least one digit and at least one lowercase letter.

Answer 3

I would recommend the hashids with a minimum length of three and a custom salt if you would like:

codes = [hasher.encode(i) for i in range(100)] # assuming hasher = hashids.Hashids('', 3)

Answer 4

I think, you want something like below:

>>> import string
>>> import random
>>> L1 = []
>>> my_chars = string.ascii_lowercase + string.digits #list of alphanumeric characters
>>> while(len(L1)<100): #To keep iterating until len(L1)=100
    s = random.sample(my_chars,3) #Pick a sample(list) of three characters len from chars list
    if not all(t in string.digits for t in s) and not all(t in string.ascii_lowercase for t in s): #Check if these characters are neither only digits nor letters, only mix of both will be allowed
        L1.append(''.join(s)) #concatenate the characters to form the string and add it to list L1


>>> len(L1)
100
>>> L1
['f3m', 'gw2', '9ua', 'm4r', 'fv5', 'jw1', 'd1b', 'lh1', 'i61', '53m', 'j6y', 'fg6', '90d', 'xz1', 'n9f', 'k6r', '31b', 'm8w', '8w1', 'h5q', 'h3d', 'ju2', 'q1i', '6ci', '07m', '40c', 's0h', 'q1p', 'u2o', 'r4g', '6gq', 'rj4', '08x', 'yr6', 'il7', '21w', 'v3q', 'kv9', 'e4i', 'g3o', 'r2p', 'nl7', 'k8h', 'by9', 'qd1', 't71', 'x8f', 'uq3', 'k2z', '5i7', '7pc', 'd68', '6n0', '81y', 'c34', 'la0', 'a0c', '1d9', '7oi', 'z7x', '8l9', '0te', 'e9b', '2yp', '17h', 'vm1', 'vm1', 'ow9', '1ma', 'y7q', '7wa', 'a6b', '9uo', '5t2', 'i40', 'ja1', '16v', '0fe', '6bc', 'ek3', 'th6', '26g', 'a9n', 'fo5', '3hg', '4wz', 'v6z', 'r7b', '9cr', 'a0s', '8yp', 'v0f', 'es4', '8do', 'd0e', 'o6z', 'x3q', 'qw3', 'gi0', '0eg']