getting file path with '/'

Question

How to get 'path/to/file/'

This is missing the last '/'

In [2]: os.path.join('path', 'to', 'file')
Out[2]: 'path/to/file'

This does not help:

In [3]: os.path.join('path', 'to', 'file', '/')
Out[3]: '/'

If you concatenate two path joins then your code shoud look like os.path.join(os.path.join('path', 'to', 'file'), os.path.join('second', 'path')) and everything will be fine. — Matthias
– Matthias, Commented Nov 3, 2015 at 8:02

Kevin · Accepted Answer · 2015-11-03 02:07:29Z

2

Just add it yourself: os.path.join('path', 'to', 'file') + os.path.sep

answered Nov 3, 2015 at 2:07

Kevin

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Comments

smertrios · Accepted Answer · 2015-11-03 02:10:14Z

1

have your tried: os.path.join('path','to','file'+os.sep)

answered Nov 3, 2015 at 2:10

smertrios

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