Sorting an array by another array with duplicate values

I think you are looking for something like this?

$words = array("hello", "my", "name", "is", "indigo");
$order = array(0, 1, 3, 2, 4);
$result = array_map(function($o) use ($words){
    return $words[$o];
}, $order);

Which produces this:

array(5) {
    [0] = string(5) "hello"
    [1] = string(2) "my"
    [2] = string(2) "is"
    [3] = string(4) "name"
    [4] = string(6) "indigo"
}

Update

I have reread your question but I am still unsure what you seek? I have updated my original code, but now 0's are removed and it is ordered largest numbers to smallest. Although if the 0's are removed you cannot access the first element of the array?

If this is not correct, perhaps you could explain what it is doing wrong, and what it needs to be doing differently. I suspect the issue is just a language breakdown.

$words = array("hello", "my", "name", "is", "indigo");
$order = array(0, 0, 4, 4, 3, 1);

$order  = array_filter($order); // remove 0's
rsort($order);                  // Largest First
$result = array_map(function($o) use ($words){
    return $words[$o];
}, $order);

Which produces this:

array(4) {
    [0] = string(6) "indigo"
    [1] = string(6) "indigo"
    [2] = string(2) "is"
    [3] = string(2) "my"
}

you want to use rsort()

solution

$arrayVariable = array(1, 1, 2, 1, 4);

rsort($arrayVariable);

here is the manual rsort()

Update

I finally figured out what was wrong with what I was doing, and fixed it. For anyone who was curious as to what I was trying to do (since I was apparently shit at it), or how I eventually did it, here's my code:

$words=array("hello","my","name","is","indigo");
$sort=array(4,3,8,0,0);
$count=0;
foreach($sort as $item){
    if ($item==0) {
        $count++;
    }
}
$cut=count($sort)-$count;
for($i=count($sort); $i>=$cut; $i--) {
    unset($sort[$i]);
    unset($words[$i]);
}
array_multisort($sort,$words);
$words=array_reverse($words);
foreach($words as $word){
    echo $word."<br>";
}

Which outputs:

name
hello
my