To get value from Json Object

Question

In the below code i am passing json object it is in the format {"Table":[{"FAMin":0,"FAMax":40,"FAGrade":"C"}]}.How to get the value from it i tried the below code it results undefined .Pls help me to overcome this issue.

 function UpdateGrade(GradeID) {
        alert(GradeID);
        $.ajax({
            type: "POST", //HTTP method
            url: "MarkorGradeSettings.aspx/GetGrade", //page/method name
            data: "{'GradeID':'" + GradeID + "'}", //json to represent argument
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            success: function (msg) {
                alert(msg.d);// I get values 
                var parsedJson = jQuery.parseJSON(msg.d);
                alert(parsedJson.Table.FAMin);//undefined

                //handle the callback to handle response                
                if (msg != 'error') {
                    //$('#messages').addClass('alert alert-success').text(response);
                    // OP requested to close the modal
                    $('#myModal').modal('hide');
                } else {
                    $('#messages').addClass('alert alert-danger').text(response);
                }

                //Now add the new items to the dropdown.

            }
        });
    }

There is no need to use Parse the variable to JSON, as it is already in JSON format as you've used dataType: "json", in AJAX config — Tushar
– Tushar, Commented Sep 20, 2015 at 7:59

charlietfl · Accepted Answer · 2015-09-20 08:01:20Z

1

Table is an array but you are treating as an object

Try:

alert(msg.d.Table[0].FAMin)

Also as noted in comments there is no need to call jQuery.parseJSON when dataType:'json' is set. jQuery will parse the response internally and return object/array in callback

answered Sep 20, 2015 at 8:01

charlietfl

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Comments

Ownaginatious · Accepted Answer · 2015-09-20 08:01:48Z

0

It looks like you missed that the data under Table is an array.

This should at least fix this particular case:

alert(parsedJson.Table[0].FAMin);

answered Sep 20, 2015 at 8:01

Ownaginatious

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