I want to create an array of 10 × 10, which contains '.' for each element. So I write as :
int A[10][10]={ '.','.','.','.',
(wait a minute I have to write 100 full stops and 100 commas)
'.','.','.'}
Another method is to write '.', 10 times and then copy paste it 10 times, but still this takes time and I don't think this is the smartest method.
Is there a smarter method? I don't want to write so long full stops.
The only feasible way to initialize an array like this, is (unfortunately) by using a flood of macros:
#define ONE_DOT '.',
#define TWO_DOTS ONE_DOT ONE_DOT
#define FIVE_DOTS TWO_DOTS TWO_DOTS ONE_DOT
#define TEN_DOTS { FIVE_DOTS FIVE_DOTS },
#define TWENTY_DOTS TEN_DOTS TEN_DOTS
#define FIFTY_DOTS TWENTY_DOTS TWENTY_DOTS TEN_DOTS
#define ONE_HUNDRED_DOTS FIFTY_DOTS FIFTY_DOTS
int A[10][10] = { ONE_HUNDRED_DOTS };
Use a for loop statement to assign all elements to '.' ----
char A[10][10];
int i,j;
for(i=0;i<10;i++)
for(j=0;j<10;j++)
A[i][j]='.';
const?Loops are the thing You want to read about now.
The simple for loop will do that for you.
char A[10][10];
int i,j;
for ( i=0;i <10;++i){
for ( j=0;j <10;++j)
A[i][j]='.';
}
For further justification google loops in c/c++
for loops go from 0 included to 0 excluded, i.e [0, 0). They won't ever be entered.const?