zip a file in python

Question

I'm trying to zip a file in python, my code is:

import zipfile
f = zipfile.ZipFile('/home/tom/Desktop/test.csv.zip','w',zipfile.ZIP_DEFLATED)
f.write('/home/tom/Desktop/test.csv')
f.close()

It's working well, but inside my zip file I'm having the full path: /home/tom/Desktop/test.csv

How can I just get test.csv inside the zip file?

Does this answer your question? How to create a zip archive of a directory in Python? — Omega Krypton
– Omega Krypton, Commented Jan 29, 2020 at 14:28

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

From docs:

ZipFile.write(filename[, arcname[, compress_type]])

Write the file named filename to the archive, giving it the archive name arcname (by default, this will be the same as filename, but without a drive letter and with leading path separators removed).

So...

f.write('/home/tom/Desktop/test.csv', 'test.csv')

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Dec 1, 2014 at 4:29

Amadan

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