ByteBuffer causing underflow exception

Question

I came across a problem when sending data over TCP with a custom protocol which relies on knowing the length of data so I decided that I could not send an int due to the size of the int could be different lengths (the int 10 has a length of 2 whereas the int 100 has a length of 3) so I decided to send a 4 byte representation of the int instead and thus I came across ByteBuffer.

With the following example I get a BufferUnderflowException

try
{
    int send = 2147483642;
    byte[] bytes = ByteBuffer.allocate(4).putInt(send).array(); // gets [127, -1, -1, -6]
    int recieve = ByteBuffer.allocate(4).put(bytes).getInt(); // expected 2147483642; throws BufferUnderflowException
    if (send == recieve)
    {
        System.out.println("WOOHOO");
    }
}
catch (BufferUnderflowException bufe)
{
    bufe.printStackTrace();
}

You've left out the flip(), but it seems pretty pointless. Throw it all away and use DataOutputStream.writeInt() and friends. — user207421
– user207421, Commented Sep 20, 2014 at 10:18

Petar Butkovic · Accepted Answer · 2014-09-20 10:27:51Z

4

You need to set start index or rewind buffer;

int recieve = ByteBuffer.allocate(4).put(bytes).getInt(0);

answered Sep 20, 2014 at 10:27

Petar Butkovic

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