javascript - Get name of function through a function [duplicate]

Question

So say, I have function Hello_world() :

function Hello_world() {
  b();
}

I want to create function b() where b() returns the name of the function in which called it. In this case I want b() returns "Hello_world".

So how should b() be constructed? Thx.

No, you don't want that. What problem are you trying to solve with this? — Bergi
– Bergi, Commented Apr 7, 2014 at 11:27

Bergi · Accepted Answer · 2014-04-07 11:36:31Z

4

You could use three despised, deprecated and non-standard properties for this:

function b() {
    return arguments.callee.caller.name;
}

Don't expect it to work in older browsers, newer browsers, strict mode, internet explorer, …

edited Apr 7, 2014 at 11:36

answered Apr 7, 2014 at 11:31

Bergi

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4 Comments

Praveen Over a year ago

+1 I was not aware of it. if it a non-standard can we pass the method name as a parameter to b(theCallerName){ return theCallerName}?

Bergi Over a year ago

Yes, you can and should, though it makes b() superfluous :-)

RobG Over a year ago

@Praveen—hopefully you'd pass a reference to the function, rather than just its name. ;-)

Bergi Over a year ago

@RobG: Actually I meant passing the name as a string is the best solution :-)

Vladimir.J.Nekiy · Accepted Answer · 2014-04-07 11:41:49Z

There is also a trick with the stack trace, which is also despised (since it's highly platform-dependent) and ugly to say the least:

function getStackTrace() { return new Error().stack; }

Which would return something like this in chrome's developer's console:

"Error
    at getStackTrace (<anonymous>:2:35)
    at <anonymous>:2:1
    at Object.InjectedScript._evaluateOn (<anonymous>:581:39)
    at Object.InjectedScript._evaluateAndWrap (<anonymous>:540:52)
    at Object.InjectedScript.evaluate (<anonymous>:459:21)"

and you go with reqular expressions from there.

Will work in Chrome, not sure for others, so it's bad for production-versions. Nice hack though :)

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