How do I deserialize json into PropertyType?

Question

I'm trying to create a new instance of a property by deserializing a json string. The call to JsonConvert.DeserializeObject<T>(string) works when I explicitly state the type of T:

var foo = JsonConvert.DeserializeObject<Resource>(propertyValue.ToString());

But I'd like to pass it PropertyInfo.PropertyType:

var foo = JsonConvert.DeserializeObject<prop.PropertyType>(propertyValue.ToString());

I get "type or namespace 'prop' could not be found." This doesn't make sense to me, I thought that PropertyType is a Type.

@SLaks Ok, is there an alternative I can try? A different approach? — Zach
– Zach, Commented Mar 20, 2014 at 19:31
Here PropertyType is a property that holds a Type; it is not a type itself. Generics must be able to be resolved at compile time. — Brian Rogers
– Brian Rogers, Commented Mar 20, 2014 at 20:38

rene · Accepted Answer · 2014-03-20 19:46:32Z

4

Take the overload that does accept a type parameter

var foo = JsonConvert.DeserializeObject(
            propertyValue.ToString(), 
            prop.PropertyType);

foo will be of type object in this case. This solves your question but you are still left with a reference to a type that is not of your prop.PropertyType.

edited Mar 20, 2014 at 19:46

answered Mar 20, 2014 at 19:38

rene

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