3

I am new to node JavaScript and do not understand the syntax too much. My code 

console.log(index+ "\t" + output[index]);

Outputs empty strings in my array.

So I have created a new method

var array = removingEmptyString(output[index]);
function removingEmptyString(array)
{
    var newArray = [];

    for(var i in array)
        {
            if(i != "" || i != null || i != " ")
                {
                    newArray[i] = i;
                }
        }

    }

What I do not understand is if I declared my arrays correct? Also if I passed int he array into the removingEmptyString correctly, also if declaring the new array and inserting the non empty string into that array are correct?

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3
  • 2
    You're never returning anything? i will be the key, not the value. Commented Nov 29, 2013 at 17:01
  • look here: stackoverflow.com/questions/281264/… Commented Nov 29, 2013 at 17:02
  • also, in js, arrays are not continuous. the way you do things, you'll have gaps instead of your empty values. Commented Nov 29, 2013 at 17:02

2 Answers 2

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2

One problem is that Arrays and Objects are slightly different things. To iterate over an array you can use things like:

for (var i=0; i<arr.length; i++) {
  /* code */
}

arr.forEach(function(item, index, arr) {
  /* code */
});

The for..in structure is used to iterate over the keys in an Object:

var obj = { b : 1, c:2 }

for (var key in obj) {
  console.log(key) // will output first b then c
}

The simplest way to remove empty values in an array is this:

var arr = [ 1, '', null, 3, 0, undefined, '', 4 ];
var filtered = arr.filter(function(item){ return item != null && item !== ''; });

console.log(filtered) // [1,3,0,4]

Obviously you can add more things that should be filtered out of your original array by changing the function passed to filter.

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4 Comments

where it says arr would i put in output[index] or just output
You put your array there. From the looks of it, it is output[index], but i can't be sure.
it did not work i still got an output of tree,,,
What are the contents of the original array?
0

Or a simple method using the filter method.

var newArray = oldArray.filter(function(v){return v!==''});
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1 Comment

where it says oldArray would i put in output[index] or just output

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