I created my test function:
void test(double** matrix);
I want to pass to this function variable as double matrix[2][2] = {{1,2},{2,3}};. But my evil compiler writes: cannot convert «double (*)[2]» to «double**» for argument «1» to «void test(double**)».
What do I need to do?
The types of the arguments and the parameters have to agree (or
at least be compatible). Here, you have a double[2][2], and
you want to pass it to a double**. The types are unrelated:
an array of arrays is not an array of pointers (which would
convert to a pointer to a pointer).
If you really want to pass a double [2][2], you'll have to
declare the parameter as a double (*matrix)[2], or (better yet),
a double (&matrix)[2][2].
Of course, if you're using C++, you'll want to define a Matrix
class, and use it.
void test(double (&matrix)[2][2]) gives error: expected ‘)’ before ‘&’ token (at least on C) is for C++?
double (*matrix)[2].
double[][]to adouble**because the memory layouts are different. You'll need to allocate your rows withnewor find another way (hint:vector).