I need to encode a javascript function into a JSON object in PHP.
This:
$function = "function(){}";
$message = "Hello";
$json = array(
'message' => $message,
'func' => $function
);
echo json_encode($json);
outputs:
{"message":"Hello","func":"function(){}"}
What I want is:
{"message":"Hello","func":function(){}}
Can I do this with json_encode?
As Jani said, this is not possible directly with JSON, but this might help you: http://web.archive.org/web/20080828165256/http://solutoire.com/2008/06/12/sending-javascript-functions-over-json/
eval instead of using a strict JSON parser.json_decode parse the given array to json string, so you can play with it as a string. Just use some unique string to indicate the start and the end of the function. Then use str_replace to remove the quotes.
$function = "#!!function(){}!!#";
$message = "Hello";
$json = array(
'message' => $message,
'func' => $function
);
$string = json_encode($json);
$string = str_replace('"#!!','',$string);
$string = str_replace('!!#"','',$string);
echo $string;
The output will be:
{"message":"Hello","func":function(){}}
preg_replace("/(\"#!!)|(!!#\")/", '', json_encode($json))No. JSON spec does not support functions. You can write your own code to output it in a JSON-like format and it should work fine though.
If don't want to write your own JSON encoder you can resort to Zend_Json, the JSON encoder for the Zend Framework. It includes the capability to cope with JSON expressions.
I wrote a small library that allows to do this. It's similar to Zend framworks's solution, but this library is much more lightweight as it uses the built-in json_encode function. It is also easier to use with external libraries, where json_encode is buried deeply in vendor code.
<?php
use Balping\JsonRaw\Raw;
use Balping\JsonRaw\Encoder;
$array = [
'type' => 'cat',
'count' => 42,
'callback' => new Raw('function(a){alert(a);}')
];
?>
<script>
let bar = <?php echo Encoder::encode($array); ?>
bar.callback('hello'); //prints hello
</script>
"require": {"php": ">=7.0"}, "require-dev": {"phpunit/phpunit": "^7.1"} unlike zend-json which has a dependency of "require": {"php": "^5.6 || ^7.0"}, "require-dev": {"phpunit/phpunit": "^5.7.23 || ^6.4.3", "zendframework/zend-coding-standard": "~1.0.0", "zendframework/zend-stdlib": "^2.7.7 || ^3.1"}. In short, your library doesn't work with php 5.6
I write this simple function for all json function based help my myabe help someone:
function json_encode_ex($array) {
$var = json_encode($array);
preg_match_all('/\"function.*?\"/', $var, $matches);
foreach ($matches[0] as $key => $value) {
$newval = str_replace(array('\n', '\t','\/'), array(PHP_EOL,"\t",'/'), trim($value, '"'));
$var = str_replace($value, $newval, $var);
}
return $var;
}
You can try this:
var json_string = '{"message":"Hello","myfunc":"function(){ alert(this.message) }"}';
var json_string = JSON.parse(json_string, function(k,v){
if(typeof v == 'string' && /function\(\)\{/.test(v)){
return eval(k+' = '+v);
}else{
return v
}
});
The enconding part in PHP is seems to be solved by now. You can use
json_encode($p, JSON_UNESCAPED_UNICODE)
this way your function will not be escaped. However
This function can also help:
function jsonify($var){
return str_ireplace(array("'function",'"function',"}'",'}"'),array("function",'function',"}",'}'),json_encode($var));
}
Taken from here: http://network.convergenceservices.in/forum/105-uknowva-development/4710-introducing-convhelperjsonify-in-uknowva-251.html#4710
