I want to create a for loop in bash that runs from 1 to a number stored in a variable in bash. I have tried doing what the answer to this question tells, but it produces this error:
Syntax error: Bad for loop variable
My OS is Ubuntu 12.04 and the code looks like this:
#!/bin/bash
TOP=10
for ((i=1; i<=$TOP; i++))
do
echo $i
done
What does this error message mean? Here is an output image:
C-style for loop works only in few shells and bash is among them. This is syntax is not part of POSIX standard.
#!/bin/bash
TOP=10
for ((i=1; i<=$TOP; i++))
do
echo $i
done
POSIX-compliant for loop will be the following
#!/bin/bash
TOP=10
for i in $(seq 1 $TOP)
do
echo $i
done
This works both in bash and sh.
To know which shell you are logged in, execute the following command
ps -p $$
Where $$ is PID of current process and the current process is your shell, and ps -p will print information about this process.
To change your login shell use chsh command.
You are running the script with sh, not bash.
Try:
bash split_history_file_test.sh
for loops. The Bash command syntax is a superset of the Bourne shell command syntax.This code doesn't produce that error. The bash version shipped with that ubuntu version should execute it without problems.
Note: you want to echo $i.
