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  • ${foo//bar/baz} must replace all bar to baz, so echo will be foobazfoobaz tldp.org/LDP/abs/html/string-manipulation.html Commented Jan 22, 2012 at 11:26
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    OP is doing global substitution using //. I don't think he wants to append bar/baz to his variable. He is looking to replace occurrences of bar with baz so that his output looks like foobazfoobaz Commented Jan 22, 2012 at 11:27
  • yeah in every bash string manipulation article use such code but it does not work for me Commented Jan 22, 2012 at 11:28