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So I need to handle this exception the same as I have if the status isnt returned as Ok correct?

ios85
– ios85

2012-01-06 16:14:50 +00:00
Commented Jan 6, 2012 at 16:14
Yes, the exception is essentially saying that the server wasn't responding within the given limit. The reason why it wasn't responding can vary. You can try and get the http code from the exception that's thrown. See this answer: stackoverflow.com/questions/3614034/…

keyboardP
– keyboardP

2012-01-06 16:28:21 +00:00
Commented Jan 6, 2012 at 16:28

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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

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[example](https://example.com)

<a href="https://example.com">example</a>

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