Return to Answer

There is an easy way...

$(arr1).not(arr2).length === 0 && $(arr2).not(arr1).length === 0

If the above returns true, both the arrays are same even if the elements are in different order.

NOTE: This works only for jquery versions < 3.0.0

There is an easy way...

$(arr1).not(arr2).length === 0 && $(arr2).not(arr1).length === 0

If the above returns true, both the arrays are same even if the elements are in different order.

NOTE: This works only for jquery versions < 3.0.0 when using JSON objects

There is an easy way...

$(arr1).not(arr2).length === 0 && $(arr2).not(arr1).length === 0

If the above returns true, both the arrays are same even if the elements are in different order.

There is an easy way...

$(arr1).not(arr2).length === 0 && $(arr2).not(arr1).length === 0

If the above returns true, both the arrays are same even if the elements are in different order.

NOTE: This works only for jquery versions < 3.0.0

There is an easy way...

$(arr1).not(arr2).length == 0 && $(arr2).not(arr1).length == 0

If the above returns true, both the arrays are same even if the elements are in different order.

There is an easy way...

$(arr1).not(arr2).length === 0 && $(arr2).not(arr1).length === 0

If the above returns true, both the arrays are same even if the elements are in different order.